Indicate the hybridization and Magnetic nature of $\mathrm{Ni}{\left(\mathrm{CO}\right)}_4$

$\mathrm{Ni}$ is in zero oxidation state in$\mathrm{Ni}{\left(\mathrm{CO}\right)}_4$.

• So the electronic configuration of Ni is $3{\mathrm{d}}^{8}4{\mathrm{s}}^2$.
• As $\mathrm{CO}$ is a strong ligand, so all the electrons  are paired in the d orbital as shown in the given diagram

so it is paramagnetic