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In ${ICl}_{3}$ oxidation numbers of iodine and chlorine are

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-1 & +3

+3 & -1

-3 & +1

0 & 0

answer is B.

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Detailed Solution

Trigonal bipyramidal

I+3(-1)=0

I-3=0

I=+3

oxidation state of chlorine =−1

In a from top to bottom E.N decreases both are halogens. Iodine has large atomic size it gets acquire positive charge.

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