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Q.

Initially a body is at rest. If its acceleration is ${6 ms}^{-2}$ , then the distance travelled in the $18^{th}$ second is

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a

86 m

b

53 m

c

105 m

d

100 m

answer is A.

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Detailed Solution

s_{n} = u + \frac{a}{2} (2 n - 1)

$= 0 + \frac{6}{2} (36 - 1)$

$= 3 \times 35$

$= 105 m$

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Initially a body is at rest. If its acceleration is 6 ms-2 , then the distance travelled in the 18th second is