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Initially a body is at rest. If its acceleration is ${6ms}^{- 2}$ then the distance travelled in the $18^{th}$ second is

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$10 5m$

$86m$

$53m$

$100 m$

answer is A.

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Detailed Solution

$u = 0, a = {6ms}^{- 2}, S_{18} = ?$

$S_{n} =u + a n - \frac{1}{2}$

$S_{18} = 0 + 6 [18 - \frac{1}{2}] = 6^{3} [\frac{35}{2_{1}}]$

$S_{18} = 105 m$

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