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Initially the circuit is in steady state when the switch S is closed the heat generated in the circuit will be

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$\frac{ε^{2} C}{2}$

$2 ε^{2} C$

$\frac{3 ε^{2} C}{2}$

Zero

answer is D.

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Detailed Solution

The potential difference across capacitor is still `E’

$\Rightarrow$ charge does not change

$\Rightarrow$ Heat dissipated =0

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