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In $∆ le ABC, 5 \cos A + 3 = 0$ then the quadratic equation whose roots are $sinA$ and $tanA$ is

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$15 x^{2} - 18 x - 16 = 0$

$15 x^{2} - 8 x - 16 = 0$

$15 x^{2} + 32 x + 16 = 0$

$15 x^{2} + 8 x - 16 = 0$

answer is B.

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Detailed Solution

$co A = \frac{- 3}{5}, \sin A = \frac{4}{5}, \tan A = \frac{- 4}{3}$

$\frac{4}{5}, \frac{- 4}{3}$ are roots of Q.E. is.

$x^{2} - (\frac{4}{5} - \frac{4}{3}) x + \frac{4}{5} (\frac{- 4}{3}) = 0 15 x^{2} + 8 x - 16 = 0$

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