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Q.

Inner surface of a cylindrical shell of length l and of material of thermal conductivity k is kept at constant temperature T1 and outer surface of the cylinder is kept at constant temperature T2 such that (T1>T2) as shown in figure. Heat flows from inner surface to outer surface radially outward. Inner and outer radii of the shell are R and 2R respectively. Due to lack of space this cylinder has to be replaced by a smaller cylinder of length  l2, inner and outer radii R4 and R respectively and thermal conductivity of material nk. If rate of radial outward heat flow remains same for same temperature of inner and outer surface i.e, T1 and  T2, then find the value of n
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answer is 4.

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Detailed Solution

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Since rate of heat flow remains same in both the cases, so

R2Rdxk2π×l=R4Rdxnk(2πx)l2nk=4kn=4

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