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Q.

Inorganic Benzene is obtained by reaction of

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a

$N H_{3} + B_{2} H_{6}$ in 2:1 ratio

b

$N H_{3} + B_{2} H_{6}$ in 1:2 ratio

c

$N H_{3} + B_{2} H_{6}$ in 1 : 4 ratio

d

$N H_{3} + B_{2} H_{6}$ in 4 : 1 ratio

answer is A.

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Detailed Solution

Inorganic Benzene = Borazole

$3 B_{2} H_{6} + 6 N H_{3} \to_{}^{523 K} 2 B_{3} N_{3} H_{6} + 12 H_{2}$

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