In $\mathrm{Pt}{\left({\mathrm{C}}_2{\mathrm{H}}_4\right)}_2\left({\mathrm{C}}_2{\mathrm{F}}_4\right)$ molecule, in which the platinum and all six carbon atoms are almost coplanar, choose the correct statement(s) 

In case of ${\underset{\_}{\mathrm{C}}}_2(\mathrm{CN}{)}_4$ in the complex above, the underlined C-hybridisation is $\underset{n\to 3}{lim} s{p}^n$

$\mathrm{C}-\mathrm{C}$ distance is greater in ${\mathrm{C}}_2{\mathrm{F}}_4\text{ than }{\mathrm{C}}_2{\mathrm{H}}_4$

If ${\mathrm{C}}_2{\mathrm{H}}_4$ is replaced by ${\mathrm{C}}_2(\mathrm{CN}{)}_4$ in the complex, then $\mathrm{C}-\mathrm{C}$ distance is greater in ${\mathrm{C}}_2\left({\mathrm{CN}}_4\right.)$ than ${\mathrm{C}}_2{\mathrm{F}}_4$ . (double bond length)

$\mathrm{Pt}-\mathrm{C}\left(\text{ of }{\mathrm{C}}_2{\mathrm{H}}_4\right)$ distance is greater than $\mathrm{Pt}-\mathrm{C} \left(\text{ of }{\mathrm{C}}_2{\mathrm{F}}_4\right)$