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Inside a hollow sphere of mass $M$ , a rod of length $R \sqrt{2}$ is released from the state of rest. The mass of the rod is same as that of the sphere. If the inner radius of the hollow sphere is $R$ then find out its horizontal displacement with respect to earth in the time in which the rod becomes horizontal.

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$R / 2$

$R / 4$

$R / 2 \sqrt{2}$

None

answer is B.

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Detailed Solution

When rod becomes horizontal $CM$ of the sphere $(C_{1})$ of rod $(C_{2})$ are in same vertical line with their combined $CM (C)$ which has no horizontal displacement.

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