Insulin is dissolved in a suitable solvent and the osmotic pressure $(π)$ of solution of various concentrations $(g / {cm}^{3})$ C is measured at $20^{0} C$ . The slope of $π$ against C is found to be $4.65 \times 10^{- 3}$ . The molecular weight of the insulin (g/mol) is: (R = 0.0821 lit atm ${mole}^{- 1} K^{- 1}$ )

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$4.5 \times 10^{5}$

$3 \times 10^{5}$

$5.16 \times 10^{6}$

$9 \times 10^{5}$

answer is D.

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Detailed Solution

$π$ =CRT.

C = concentration in mole/lit

when expressed in gm/ cc

$C = \frac{C}{Molar mass (M)} \times \frac{1000}{v (ml)}$

$π$ $= \frac{C}{M} \times 1000 RT$

Slope $= \frac{1000 RT}{M}$

$4.65 \times 10^{- 3} = \frac{1000 \times 0.0821 \times 293}{M}$

M = $\frac{1000 \times 0.0821 \times 293}{4.65 \times 10^{- 3}}$

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