Integrating factor of xdydx=2y+2x4+x2

dydx−2yx=2x3+x ∴I.F=∫−2xdx=x−2

Integrating factor of xdydx=2y+2x4+x2

dydx−2yx=2x3+x ∴I.F=∫−2xdx=x−2

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$Integrating factor of x \frac{d y}{d x} = (2 y + 2 x^{4} + x^{2})$

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$x$

$x^{- 1}$

$x^{2}$

$x^{- 2}$

answer is A.

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$\frac{d y}{d x} - \frac{2 y}{x} = 2 x^{3} + x ∴ I . F = \int \frac{- 2}{x} d x = x^{- 2}$

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$Integrating factor of x \frac{d y}{d x} = (2 y + 2 x^{4} + x^{2})$