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Q.

Intensity of light incident on a photo sensitive surface is doubled. Then

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a

the number of emitted electrons is trippled.

b

the number of emitted electrons is doubled.

c

the K.E. of emitted electrons is doubled.

d

the momentum of emitted electrons is doubled.

answer is B.

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Detailed Solution

Given Data:

Intensity of light incident on a photo sensitive surface is doubled.

Detailed Solution:

Number of emitted electrons depends on the intensity of incident light. More is the intensity of incident light, more will be the number of electrons hitting the surface and more will be the number of electrons ejected from the surface.
by doubling the intensity, the numbers of emitted electrons is also doubled.

Hence, the correct option is B.

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