Intensity of progressive sound wave can be doubled by increasing

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Intensity of progressive sound wave can be doubled by increasing

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amplitude by 50%

amplitude by 41 %

frequency by 50 %

frequency by 41 %

answer is B, D.

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Detailed Solution

$\begin{array}{ll} I \propto a^{2} and I \propto v^{2} \\ \Rightarrow \frac{I_{2}}{I_{1}} = 2 = {(\frac{v_{2}}{v_{1}})}^{2} \\ \Rightarrow v_{2} = \sqrt{2} v_{1} = 1.41 v_{1} \end{array}$

and $\frac{I_{2}}{I_{1}} = {(\frac{a_{2}}{a_{1}})}^{2} = 2 \Rightarrow a_{2} = \sqrt{2} a_{1} = 1.41 a$

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