Banner 0
Banner 1
Banner 2
Banner 3
Banner 4
Banner 5
Banner 6

Q.

Internal energy of an ideal diatomic gas at 300K is 100 J . Out of this 100 J,

see full answer

Talk to JEE/NEET 2025 Toppers - Learn What Actually Works!

Real Strategies. Real People. Real Success Stories - Just 1 call away
An Intiative by Sri Chaitanya

a

Rotational kinetic energy is 40 J.

b

Translational kinetic energy is 60 J 

c

Potential energy is zero

d

Translational kinetic energy is 100 J

answer is A, B, C.

(Unlock A.I Detailed Solution for FREE)

Ready to Test Your Skills?

Check your Performance Today with our Free Mock Test used by Toppers!

Take Free Test

Detailed Solution

Potential energy of an ideal gas is zero because inter molecular forces between them is zero. Degree of freedom of an ideal diatomic gas is 5. In this 2 is rotational and 3 is translational. According to  law of equipartition of energy  internal energy is equally distributed in all degrees of freedom.
Therefore, rotational kinetic energy =  23×100=40J
               Translational kinetic energy =  35×100=60J
 

Watch 3-min video & get full concept clarity

Best Courses for You

JEE

JEE

NEET

NEET

Foundation JEE

Foundation JEE

Foundation NEET

Foundation NEET

CBSE

CBSE

score_test_img

Get Expert Academic Guidance – Connect with a Counselor Today!

whats app icon