In ${XeF}_{2}$ , molecule the angle between two lone pair orbitals is $α$ . the angle between lone pair orbital and bond pair orbital is $β$ and the angle between bond pair orbitals is $γ$ :

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$γ > α > β$

$\begin{aligned} α = β = γ \end{aligned}$

$\begin{aligned} α > β > γ \end{aligned}$

$γ > β > α$

answer is D.

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Detailed Solution

For ${XeF}_{2}$ , molecule

The angle between two lone pair orbitals is $α = 120^{\circ}$

The angle between lone pair orbital and bond pair orbital is $β = 90^{\circ}$

The angle between bond pair orbitals is $γ = 180^{\circ}$ .

Hence the correct order is, $γ > α > β$ .

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