Xenon (Xe) is bonded to two fluorines (left: 184 pm, right: 235 pm).The right-side fluorine bridges to Sb (antimony), which is bonded to six F atoms.The lower Sb is also octahedrally surrounded by six F atoms.

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In $X e F_{2} .2 S b F_{5}$

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F is forming bridge between Xe and Sb

These are two Xe - F bond with bond lengths 184 pm and 235 pm

Both (1) and (2) are correct

neither (1) nor (2) is correct

answer is C.

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Detailed Solution

Xenon (Xe) is bonded to two fluorines (left: 184 pm, right: 235 pm).
The right-side fluorine bridges to Sb (antimony), which is bonded to six F atoms.
The lower Sb is also octahedrally surrounded by six F atoms.

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