Iodiine atom, in the third excited state, reacts with fluorine to form a compound ‘x’. The formula and shape of ‘x’ are

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IF₄ ,tetrahedral

IF₅ ,pentagonal

IF₄ , pentagonal bipyramidal

IF₇ , pentagonal bipyramidal

answer is D.

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Detailed Solution

In third excited state, Iodine has the outermost configuration : ns¹np³ nd³ , in its velence shell it has 7 unpaired electrons.

Thus it forms IF₇.Its hybridisation is sp³d³ .Shape is pentagonal bipyramidal.

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