Iodine molecule dissociates into atoms after absorbing light of 450 $0^{o}$ A . If one quantum of radiation is absorbed by each molecule, calculate the kinetic energy of Iodine atoms. (Bond energy of $I_{2} = 240 KJ {mol}^{- 1}$

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$2.16 \times 10^{- 20} J$

$2.16 \times 10^{- 22} J$

$4.1 \times 10^{- 20} J$

$3.12 \times 10^{- 14} J$

answer is A.

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Detailed Solution

Given bond energy of

$I_{2} = 240 \times {KJmol}^{- 1}$

$= 240 \times 10^{3} J {mol}^{- 1}$

Hence, bond energy of each molecule

$\frac{6.623 \times 10^{- 34} - 3 \times 10^{8}}{4500 \times 10^{- 10}}$

$= 4.417 \times 10^{- 19} J$

K.E of one $I_{2}$ molecule= $4.417 \times 10^{- 19} - 8.965 \times 10^{- 19}$

$= 0.432 \times 10^{- 19}$

K.E of each atom= $\frac{0.482 \times 10^{- 19}}{2} = 0216 \times 10^{- 19} J$

$= 2.16 \times 10^{- 20} J$

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