Iodo benzene is prepared from aniline $\left({\mathrm{C}}_6{\mathrm{H}}_5{\mathrm{NH}}_2\right)$ in a two step process as shown here

${\mathrm{C}}_6{\mathrm{H}}_5{\mathrm{NH}}_2+{\mathrm{NaNO}}_2+\mathrm{HCl}\to {\mathrm{C}}_6{\mathrm{H}}_5{\mathrm{N}}_2+{\mathrm{Cl}}^{-}+2{\mathrm{H}}_2\mathrm{O}+\mathrm{Nacl}$

${\mathrm{C}}_6{\mathrm{H}}_5{\mathrm{N}}_2+{\mathrm{Cl}}^{-}+\mathrm{KI}\to {\mathrm{C}}_6{\mathrm{H}}_5\mathrm{I}+{\mathrm{N}}_2+\mathrm{KCl}$

In an actual preparation of 9.30 g of aniline was converted to 10.2 g of iodo benzene. The percent yield of iodo benzene is