Iodometric titration is based on the following reaction I2( s)+I-⟶I3-.The equivalent weight of iodine in reaction is

Book Online Demo

Check Your IQ

Try Test

Courses

Offline Centres

Iodometric titration is based on the following reaction $I_{2 (s)} + I^{-} ⟶ I_{3}^{-}$ .The equivalent weight of iodine in reaction is

see full answer

Start JEE / NEET / Foundation preparation at rupees 99/day !!

21% of IItians & 23% of AIIMS delhi doctors are from Sri Chaitanya institute !!

An Intiative by Sri Chaitanya

$\frac{3 M}{2}$

$\frac{M}{3}$

$\frac{M}{4}$

answer is C.

(Unlock A.I Detailed Solution for FREE)

Ready to Test Your Skills?

Check your Performance Today with our Free Mock Test used by Toppers!

Take Free Test

Detailed Solution

Given, Chemical reaction is

$I_{2 (s)} + I^{-} ⟶ I_{3}^{-}$

The oxidation state of I(terminal) changes from 0 to –1

The oxidation state of I(central) changes from -1 to 0

valence factor=3

$Equivalent weight = \frac{Mol. w t}{valence factor}$

So, $Equivalent weight = \frac{M}{3}$

Therefore, option C is correct.

Watch 3-min video & get full concept clarity

JEE

NEET

Foundation JEE

Foundation NEET

CBSE