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Ion exchange resin can replace Ca²⁺ ions in hard water with H⁺ ions:
${RH}_{2} + {Ca}^{2 +} ⟶ RCa + 2 H^{+}$
1L of hard water sample after passing through the resin shows pH = 2. What is ppm of Ca²⁺ ions in water sample? [Atomic weight : Ca = 40].

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100

400

200

300

answer is B.

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Detailed Solution

$[H^{+}] = 10^{- 2} M mol of H^{+} = 10^{- 2} mol mol of {Ca}^{2 +} = \frac{10^{- 2}}{2} mol ppm of {Ca}^{2 +} = \frac{\frac{10^{- 2}}{2} \times 40}{1000} \times 10^{6} = 200$

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