Ionic conductance of Ba²⁺ and Cl− are $\land_{1}$ mho cm² mole^-1 and $\land_{2}$ mho cm² mole^-1. Equivalent conductance of BaCl₂ will be ______ mho cm² g eq^-1.

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$\frac{\land_{1} + 2 \land_{2}}{2}$

$\land_{1} + 2 \land_{2}$

$\land_{1} + \land_{2}$

$2 (\land_{1} + \land_{2})$

answer is A.

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Detailed Solution

$\begin{array}{l} \land_{{BaCl}_{2}}^{m} = \land_{{Ba}^{2 +}}^{m} + 2 \land_{{Cl}^{-}}^{m} \\ \land_{1} + 2 \land_{2} \\ \land_{eq} = \frac{\land_{m}}{valency} = \frac{\land_{1} + 2 \land_{2}}{2} \end{array}$

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