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Ionisation energy of He⁺ is 19.6 × 10^–18J atom^-1. The energy of the first stationary state of Li²⁺ is

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– 4.41 × 10^–17 J.atom^–1

– 4.41 × 10^–16 J.atom^–1

– 4.41 × 10^–18 J.atom^–1

– 8.72× 10^–18 J.atom^–1

answer is B.

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Detailed Solution

$I E = - E_{1} E_{1} f o r H e = = 19.6 X 10^{- 18} J / a t o m$

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