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Q.

Ionization potential of hydrogen atom is 13.6 eV.Hydrogen atom in ground state are excited by monochromatic light of energy 12.1eV.The spectral lines emitted by hydrogen according to Bohr’s theory will be

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a

One

b

Two

c

Three

d

Four

answer is C.

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Detailed Solution

After absorbing 12.09 eV the electron in H atom is excited to 3 shells.

En−E1=−13.6n2−(−13.6)=12.09

−13.6n2+13.6=12.09

∴ n=3

The possible transition are ∑(3−1)=3

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