Ionization energy for hydrogen atom in the ground state is E. What is the ionization energy of Li⁺⁺ atom in the second excited state ?

The second excited state Li⁺² ground state of H Energy is E

IE of Li⁺² =IE of H in ground state $\times \frac{{\mathrm{Z}}^2}{{\mathrm{n}}^2}$

$=E\mathit{\times }\frac{3^2}{3^2}$

E = Energy of H in Ground state.