Ionization potential of hydrogen atom is 13 .6 V. Hydrogen atoms in the ground state are excited by monochromatic radiation of photon energy 12.1 eV. The spectral lines emitted by hydrogen atoms according to Bohr's theory will be

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four

three

two

one

answer is C.

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Detailed Solution

Final energy of electron = -13.6 +12.1 = -1.51 eV,
which corresponds to third level i.e., n = 3.
Hence number of spectral lines emitted $= \frac{n (n - 1)}{2} = \frac{3 (3 - 1)}{2} = 3$

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