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$I_{P}$ represent polarising angle. Limiting angles of $I_{P}$ are

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$0^{0} \leq I_{p} \leq 45^{0}$

$30^{\circ} \leq I_{p} \leq 60^{\circ}$

$0^{\circ} \leq I_{p} \leq 30^{\circ}$

$45^{\circ} \leq I_{p} \leq 90^{\circ}$

answer is B.

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Detailed Solution

$μ = \tan I_{p}$

$μ lies between 1 and \infty$

$For μ = 1, \tan I_{p} = \tan 45^{o}$

$For μ = \infty, \tan I_{p} = \tan 90^{o}$

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