Iron can be obtained by reduction of iron oxide (Fe3O4) with CO according to the reaction:Fe3O4 + 4CO → 3Fe + 4CO2How many kilograms of Fe3O4 should be heated with CO to get 3 kg of iron?

Fe3O4232 g+4CO→3Fe56×3 =168 g+4CO23 moles of Fe is produced from 1 mole of Fe3O4168 g of Fe is produced from 232 g of Fe3O43 kg of Fe will be produced from 232168×3000 g= 4142.8 g or 4.14 kg of Fe3O4

Iron can be obtained by reduction of iron oxide (Fe3O4) with CO according to the reaction:Fe3O4 + 4CO → 3Fe + 4CO2How many kilograms of Fe3O4 should be heated with CO to get 3 kg of iron?

Fe3O4232 g+4CO→3Fe56×3 =168 g+4CO23 moles of Fe is produced from 1 mole of Fe3O4168 g of Fe is produced from 232 g of Fe3O43 kg of Fe will be produced from 232168×3000 g= 4142.8 g or 4.14 kg of Fe3O4

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Iron can be obtained by reduction of iron oxide (Fe₃O₄) with CO according to the reaction:
Fe₃O₄+ 4CO → 3Fe + 4CO₂
How many kilograms of Fe₃O₄ should be heated with CO to get 3 kg of iron?

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8.12 kg

4.14 kg

6.94 kg

16.8 kg

answer is B.

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Detailed Solution

$\underset{232 g}{{Fe}_{3} O_{4}} + 4 CO \to \underset{56 \times 3 = 168 g}{3 Fe} + 4 {CO}_{2}$
3 moles of Fe is produced from 1 mole of Fe₃O₄
168 g of Fe is produced from 232 g of Fe₃O₄
3 kg of Fe will be produced from $\frac{232}{168} \times 3000 g$
= 4142.8 g or 4.14 kg of Fe₃O₄