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Q.

Iron has a density of $7.86 g {cm}^{- 3}$ and an atomic mass of $55.85 amu.$ The volume occupied by 1 mol of Fe is

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a

$0.141 {cm}^{3} {mol}^{- 1}$

b

$7.11 {cm}^{3} {mol}^{- 1}$

c

$4.28 \times 10^{4} {cm}^{3} {mol}^{- 1}$

d

$22.8 {cm}^{3} {mol}^{- 1}$

answer is B.

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Detailed Solution

Molar volume $= \frac{Molar mass}{density} = \frac{55.85 g {mol}^{- 1}}{7.86 g {cm}^{- 3}} = 7.11 {cm}^{3} {mol}^{- 1}$

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