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Q.

⨍  is a function defined as k=1n⨍ (a+k)=16(2n-1) and ⨍ (x+y)=⨍ (x).⨍ (y) and ⨍ (1)=2 the integral value of a

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a

3

b

0

c

2

d

1

answer is A.

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Detailed Solution

⨍ (x+y)=⨍ (x).⨍ (y) and ⨍ (1)=2

⇒⨍ (x)=2x

k=1n⨍ (a+k)=16(2n-1) 2ak=1n2k=16(2n-1) 2a2+22+23+.....+2n=16(2n-1) 2a2(2n-1)2-1=16(2n-1)⇒a=3 

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