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Q.

______ is an expression of capacitance of a spherical capacitor.


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a

Question Image

b

Question Image

c

Question Image

d

None of these 

answer is A.

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Detailed Solution

Concept:
                                                       Question ImageConsider a spherical capacitor having +Q charge on the inner surface
–Q on the outer surface.
 Let R and r be the radii of the outer surface and inner surface respectively.
These two charged surfaces are separated by a radial distance of (R-r).
 Let the potential at the inner spherical surface be V1
 and potential at the outer spherical surface be V2
Let C be the required capacitance of the assumed spherical capacitor.
 As we know that the electric field due to a charged sphere having charge on the surface Q and radius r is given by
Question Image where Question Image denotes the permittivity in vacuum (Question Image Farad/metre)
Using above equation, electric field due to inner spherical surface having charge +Q and radius r is given by
Question Image-------------1
We knew that relation between electric field and potential difference
Question Image----------------2
 By comparing equations (1) and (2) ,
we can see that the LHS of both these equations are same
hence, the RHS of both these equations will be equal
Question Image=Question Image  Question ImageIntegrating on both sides,Question Image  can be taken outside the integration as it is constant.Question Image  Where ΔV=V2−V1 represents the increase in potential produced when moving from the inner spherical surface to the outer spherical surface
capacitance of any capacitor=
Question ImageBy substituting equation (3) in the above equation
Question ImageThe above equation gives the expression for the capacitance of the spherical capacitor with inner surface radius as r and outer surface radius as R.              Hence, option 1 is correct
          
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