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Is it true that in a series electrical circuit comprising a resistor made up of a metallic wire, the ammeter reads $5 A$ and the reading of the ammeter will decrease [245][246]to half when the length of the wire is doubled?

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Detailed Solution

[249][250]
The above statement is True.
When the conductor's length directly affects the resistance (

R

), as the length is increased, resistance rises and current falls.
The circuit is carrying

5 A

of current. That is,

I = V / R

I = 5 A

Due to the length and resistance being proportionate, when the length is doubled, so does the resistance. That is,

{I'}^{} = V / 2 R

{I'}^{} = 5 / 2

{I'}^{} = 2.5 A

[251][252]
Therefore, when the conductor's length is doubled, The reading on the ammeter is halved.

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