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Q.

Is it true that the apparent weight is zero during the free fall?


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a

True

b

False 

answer is A.

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Detailed Solution

The above statement is True.
An object's weight is how gravity pulls thereon, but apparent weight may be a measure of downward force. At the same time, weight may be a measure of the force exerted by gravity.
As we all know, downward forces can be manipulated easily using inertial and non-inertial reference frames (in the case of elevator/thriller rides) or using buoyancy force (in the case of fluid) or due to air drag as the object falls on the surface of the earth.
When an object falls from a specific height under the gravitational field of the earth, the autumn is called free fall, so during free fall, the acceleration remains constant.
Suppose a body mass m resting on an imaginary plane is falling down.
Let the acceleration is a (due to gravitational attraction)
Force of reaction of the plane on the body be R (upwards)
Then we can write
mg-R=ma =>-R=ma-mg =>R=mg-ma =>R=m(g-a) For a freely falling body a=g Thus R=m(g-g)
=>R=m×(0) =>R=0 Hence, the reaction force acting on the body is zero and thus its apparent weight is zero.
  
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Is it true that the apparent weight is zero during the free fall?