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Is it true that the equation of motion for a freely falling body in terms of distance traveled(s), time taken(t), and its acceleration(g), is $s = \frac{1}{2} g t^{2}$ ?

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False

answer is A.

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Detailed Solution

The above statement is true.
According to the second equation of motion, the distance travelled by a body in time,

(t)

having initial velocity

u

, and acceleration,

(a)

is,

S = ut + \frac{1}{2} a t^{2}

If the motion is under free fall then,
initial velocity(

u

) would be

= 0

Acceleration(

a

) will be acceleration due to gravity,

= g

S =

0 \times t + \frac{1}{2} g t^{2}

S = \frac{1}{2} g t^{2}

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