_____ is the area of following polygon. If AC = 10 cm, AD = 12 cm, BL = 3 cm, CM = 7 cm and EN = 5 cm.

$\begin{array}{rcl} & & Area of pentagon ABCDE\\ & =& (Area of \Delta ABC)+(Area of \Delta ACD)+(Area of \Delta ADE)\\ & =& (\frac{1}{2}\times AC\times BL)+(\frac{1}{2}\times AD\times CM)+(\frac{1}{2}\times AD\times EM)\\ & =& \left(\frac{1}{2}\times 10\times 3\right)+\left(\frac{1}{2}\times 12\times 7\right)+\left(\frac{1}{2}\times 12\times 5\right)\\ & =& 15+42+30\\ & =& 87 c{m}^2\end{array}$