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Q.

Isobutane on bromination forms tertiary butyl bromide (A) and isobutyl bromide (B). The percentage of A and B respectively when free radical bromination order is 1 : 82 : 1600  on 10, 20 and  30 hydrogen atoms is

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a

0.6% ,99.4%

b

99.4% ,0.6%

c

80% ,20%

d

50% ,50%

answer is A.

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Detailed Solution

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30=16001609×100=99.4%

10H=9×130H=1×1600

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