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Q.

Isobutane reacts with chlorine in sunlight to produce 1-Chloro-2-methyl propane 68% and 2-Chloro-2-methyl propane 32% of the total yield. Under similar conditions propane reacts with chlorine in sunlight to produce 1-Chloropropane 45% & 2-Chloropropane 55% of total yield.
The percentage yield of the major product obtained by monochlorination of 1,3,5 -trimethyl cyclohexane is $x \times 10 %$ . The value of $x$ will be

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answer is 5.

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Detailed Solution

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From given datas we will get the reactivity order of hydrogen’s which is $1 : 3.66 : 4.23$

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$P_{1} : P_{2} : P_{3} = n_{1} r_{1} : n_{2} r_{2}; n_{3} r_{3} = 1 \times 9 : 6 \times 3.66 : 3 \times 4.23 = 9 : 21.96 : 12.70 % o f P_{2} (m a j o r) = 50 X = 5$

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Isobutane reacts with chlorine in sunlight to produce 1-Chloro-2-methyl propane 68% and 2-Chloro-2-methyl propane 32% of the total yield. Under similar conditions propane reacts with chlorine in sunlight to produce 1-Chloropropane 45% & 2-Chloropropane 55% of total yield. The percentage yield of the major product obtained by monochlorination of 1,3,5 -trimethyl cyclohexane is x×10%. The value of x will be