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Q.

Isobutyraldehyde on reaction with formaldehyde and $K_{2} C O_{3}$ gives compound ‘A’. Compound ‘A’ reacts with KCN and yields compounds B. Which on hydrolysis gives a stable compound ‘C’. The compound ‘C’ is

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a

${HO-CH}_{2} - C_{\underset{{CH}_{3}}{|}}^{\overset{{CH}_{3}}{|}} - \underset{\underset{OH}{|}}{CH} -COOH$

b

${HO-CH}_{2} {CH}_{2} - {CH}_{\underset{{CH}_{3}}{|}}^{} - \underset{\underset{OH}{|}}{CH} -COOH$

c

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d

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answer is C.

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Detailed Solution

${CH}_{3} - \overset{\overset{{CH}_{3}}{|}}{CH} - \overset{\overset{O}{||}}{C} -H$
$↓ K_{2} {CO}_{3}$
${CH}_{3} - C_{(-)}^{\overset{{CH}_{3}}{|}} - \overset{\overset{O}{||}}{C} -H$
$↓ H- \overset{\overset{O}{| |}}{C} -H$
${CH}_{3} - C_{\underset{{CH}_{2} OH}{|}}^{\overset{{CH}_{3}}{|}} - \overset{\overset{O}{| |}}{C} -H$
$↓ K \overset{(-)}{C} N$
$H_{3} C- C_{\underset{{CH}_{2} OH}{|}}^{\overset{{CH}_{3}}{|}} - \overset{\overset{O^{(-)}}{|}}{C} H-CN$
$↓ H_{3} O^{+}$
$H_{3} C- C_{\underset{{CH}_{2} OH}{|}}^{\overset{{CH}_{3}}{|}} - \overset{\overset{OH}{|}}{C} H-COOH$
$↓$
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Isobutyraldehyde on reaction with formaldehyde and K2CO3 gives compound ‘A’. Compound ‘A’ reacts with KCN and yields compounds B. Which on hydrolysis gives a stable compound ‘C’. The compound ‘C’ is