Isohydric solutions are the solutions having the same concentration of hydronium ion. If 0.2 M HA (monobasic acid) solution is isohydric with $4 \times 10^{- 4} M H C l$ solution, then $K_{b}$ for $A^{-}$ is

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$1.25 \times 10^{- 8}$

$8 \times 10^{- 7}$

$8 \times 10^{7}$

$1.25 \times 10^{- 6}$

answer is B.

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Detailed Solution

Ans: B
Sol :
For weak acid HA
$[H^{+}] = \sqrt{K a . C} 4 \times 10^{- 4} = \sqrt{K a \times 0.2} K a = 8 \times 10^{- 14} K_{a} . K_{b} = 10^{- 14} K_{b} = 1.25 \times 10^{- 8}$

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