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Q.

Isopropyl alcohol on heating with acidified KMnO₄ gives

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a

One mole CH₃COCH₃

b

Two moles of HCOOH

c

CH₃COOH and CO₂

d

CO₂ and H₂O

answer is C.

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Detailed Solution

${CH}_{3} - CHOH - {CH}_{3} \to_{H^{+}}^{{KMnO}_{4}} {CH}_{3} - CO - {CH}_{3} \to_{H^{+}}^{{KMnO}_{4}} {CH}_{3} COOH + {CO}_{2} + H_{2} O$

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Isopropyl alcohol on heating with acidified KMnO4 gives