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It is an experimental fact that ${Cs}_{2} [{CuCl}_{4}]$ is orange coloured but ${({NH}_{4})}_{2} [{CuCl}_{4}]$ is yellow. It is further known that total paramagnetic moment of an unpaired electron is due to spin as well as due to nature of orbital; d orbital contributing more than s or p. Thus the total paramagnetic moment of orange compound is found to be more than that of yellow compound. Then which of the following is correct?

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Anion of orange compound is tetrahedral and that of yellow is square planar

Anion of orange compound is square planar and that of yellow is tetrahedral

Both the anions are tetrahedral

Both the anions are square planar

answer is A.

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Detailed Solution

Since the unpaired electron is not in 3d rather in some promoted state 's' or 'p anion of orange compound is tetrahedral and that of yellow is square planar.

Hence, option A is correct.

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