It is desired to change pH of 0.05 M acetic acid solution to 1.5 times pH value, the solution should be diluted to

$\mathrm{pH}=1.5\times 3.02=4.53$

$\left[{\mathrm{H}}^{+}\right]-\left({10}^{-\mathrm{pH}}\right)\mathrm{M}-2.95\times {10}^{-5}\mathrm{M}$

$c-{\left[{\mathrm{H}}^{+}\right]}^2/K_{\mathrm{a}}-{\left(2.95\times {10}^{-5}\mathrm{M}\right)}^2/\left(1.8\times {10}^{-5}\mathrm{M}\right)-4.84\times {10}^{-5}\mathrm{M}$

Dilution factor $=\frac{0.05\mathrm{M}}{4.84\times {10}^{-5}\mathrm{M}}=1033.3$