It is estimated that the energy released in the explosion of atomic bomb at Hiroshima was 9×1013J. If an average 200MeV of energy is released in the fission of one 92U235 . The mass of uranium used for the bomb is nearly

n=E1E;n=9×101332×10−12=2.812×1024 ∴E1=nEm=nMNA=2.812×1024×2356×1023g= 110.156×10 = 1101.56gm = 1.1kg

It is estimated that the energy released in the explosion of atomic bomb at Hiroshima was 9×1013J. If an average 200MeV of energy is released in the fission of one 92U235 . The mass of uranium used for the bomb is nearly

n=E1E;n=9×101332×10−12=2.812×1024 ∴E1=nEm=nMNA=2.812×1024×2356×1023g= 110.156×10 = 1101.56gm = 1.1kg

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It is estimated that the energy released in the explosion of atomic bomb at Hiroshima was 9×10¹³J. If an average 200MeV of energy is released in the fission of one ₉₂U²³⁵ . The mass of uranium used for the bomb is nearly

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4kg

1.1 kg

2.5kg

3.6 kg

answer is A.

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Detailed Solution

$\begin{array}{l} n = \frac{E^{1}}{E}; n = \frac{9 \times 10^{13}}{32 \times 10^{- 12}} = 2 .812 \times 10^{24} (∴ E^{1} = nE) \\ m = \frac{nM}{N_{A}} = \frac{2 .812 \times 10^{24} \times 235}{6 \times 10^{23}} g \end{array}$
= 110.156×10 = 1101.56gm = 1.1kg