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Q.

It is found that when waves from two identical coherent sources superpose at a certain point, then the resultant intensity is equal to the intensity of one wave only. This means that the phase difference between the two waves at that point is

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a

$\frac{2 π}{3}$

b

$π$

c

$\frac{π}{3}$

d

Zero

answer is C.

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Detailed Solution

Resultant intensity $= 4 a^{2} \cos^{2} δ / 2 a^{2} \to$ individual intensity

$\cos^{2} δ / 2 = \frac{1}{4} δ / 2 = 60^{o} δ = 120^{o} = \frac{2 π}{3}$

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