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Q.

It is known that atom contain protons, neutrons and electrons. If the mass of neutron is assumed to half of its original value whereas that of proton is assumed to be twice of its original value then the atomic mass of $_{6}^{14} C$ will be :

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a

14.28% more

b

28.56% less

c

14.28% less

d

same

answer is C.

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Detailed Solution

No. of protons in ₆C¹⁴ = 6;
No. of neutrons in ₆C¹⁴ = 8;
As per given new atomic mass of
₆C¹⁴ = 12 + 4 = 16
(As the mass of e is negligible as compared to neutron and proton)
% increase in mass $= \frac{16 - 14}{14} \times 100 = 14 .28$

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