It is known that atom contain protons, neutrons and electrons. If the mass of neutron is assumed to half of its original value whereas that of proton is assumed to be twice of its original value then the atomic mass of $_{6}^{14} C$ will be:

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same

14.28% less

14.28 more

28.56% less

answer is C.

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Detailed Solution

No,of protons in $_{6} C^{14} = 12 + 4 = 16$

No.of neutrons in $_{6} C^{14} = 8 :$

(As the mass of $e^{-}$ is negligible as compared to neutron and proton)

$%$ increase in mass $= \frac{16 - 14}{14} \times 100 = 14.28$

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