Q.

IUPAC name for following compound

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a

 4 - Ethynyl Pent - 1 - ene

b

4 - Methyl - hex - 1 - ene - 5 - yne

c

3 - Methyl hex - 5 - en - 1 - yne

d

2 - Ethynyl Pent - 4 - ene

answer is B.

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Detailed Solution

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The structure in the image shows a compound with:

  1. A double bond (alkene) and a triple bond (alkyne) in the same molecule.
  2. A methyl substituent attached to the main chain.

Steps to name the compound:

  1. Identify the parent chain: The longest chain containing both the double and triple bonds is chosen as the parent chain. The numbering starts from the end closer to the double or triple bond.
  2. Prioritize double and triple bonds: In IUPAC nomenclature, the double bond is given priority in numbering if it occurs at the same position as the triple bond.
  3. Numbering and substituent: Number the chain such that the substituent and bonds (double and triple) get the lowest numbers.

Structure analysis:

  • Parent chain: 6 carbons (hex-).
  • The double bond is between carbon 1 and 2 (1-en).
  • The triple bond is between carbon 4 and 5 (4-yne).
  • A methyl group is attached to carbon 3.

Final IUPAC Name:

3-Methylhex-1-en-4-yne

Let me know if you'd like further clarification!

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