IUPAC name of the compound ‘A’ in the following reaction is? 

${\mathrm{CH}}_3{\left({\mathrm{CH}}_2\right)}_6-\stackrel{\stackrel{\mathrm{O}}{\left|\right|}}{\mathrm{C}}-{\mathrm{OC}}_2{\mathrm{H}}_5\underset{\mathrm{ii}){\mathrm{H}}_2\mathrm{O}}{\overset{\mathrm{i})\mathrm{DIBAL}-\mathrm{H}}{\to }}\text{'}\mathrm{A}\text{'}$

‘A’ is an aldehyde $\stackrel{8}{\mathrm{C}}{\mathrm{H}}_3-\stackrel{7}{\mathrm{C}}{\mathrm{H}}_2-\stackrel{6}{\mathrm{C}}{\mathrm{H}}_2-\stackrel{5}{\mathrm{C}}{\mathrm{H}}_2-\stackrel{4}{\mathrm{C}}{\mathrm{H}}_2-\stackrel{3}{\mathrm{C}}{\mathrm{H}}_2-\stackrel{2}{\mathrm{C}}{\mathrm{H}}_2-\stackrel{1}{\mathrm{C}}\mathrm{HO}$

DIBAL-H is reducing agent C₄ is used for reduction.
In the reaction, reduction of ester gives aldehyde.
IUPAC name of aliphatic open chain aldehyde are derived from the names of the 
corresponding alkanes by replacing the ending –‘e’ with –al.