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I⨍  ⨍ (x)=ax+a2ax, then ⨍ '(a)=……

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Given f(x)=ax+a2ax differentiate w.r.to x on both sides ⨍ '(x)=a×12x+aa-12x-3/2 sub x=a on both sides ⇒⨍ '(a)=a×12a-12aaa-3/2=12-12=0.


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